{"label": "pie_cpp_test_001506", "metadata": {"data_source": "pie-cpp-perf", "gem5_cycles": 11, "hidden_test_count": 1, "problem_id": "p03766", "reference_metric": "runtime_cpu_ns", "reference_value": 11, "source_task_path": "/workspace/runs/pie-tasks-full-20260706/test/pie_cpp_test_001506.json", "split": "test", "subset": "eval", "task_id": "pie_cpp_test_001506", "task_path": "tasks/test/pie_cpp_test_001506.json", "visible_test_count": 1}, "problem_id": "p03766", "prompt": "Optimize the following C++20 program while preserving its exact behavior.\nReturn exactly one ... block followed by exactly one fenced cpp code block.\nDo not mention or rely on hidden tests. The program must read stdin and write stdout.\n\nVisible tests:\nInput:\n2\n\nExpected output:\n4\n\n\nProgram:\n```cpp\n#include \n\nusing namespace std;\n\n#define int long long\n\n#define in ({int x=0;int c=getchar(),n=0;for(;!isdigit(c);c=getchar()) n=(c=='-');for(;isdigit(c);c=getchar()) x=x*10+c-'0';n?-x:x;})\n\nmt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\n\nint rnd(int l,int r){return l+rng()%(r-l+1);}\n\n#define fasty ios_base::sync_with_stdio(0),cin.tie(0);\n\n#define forinc(a,b,c) for(int a=b,_c=c;a<=_c;++a)\n\n#define fordec(a,b,c) for(int a=b,_c=c;a>=_c;--a)\n\n#define forv(a,b) for(auto&a:b)\n\n#define fi first\n\n#define se second\n\n#define pb push_back\n\n#define ii pair\n\n#define mt make_tuple\n\n#define all(a) a.begin(),a.end()\n\n#define reset(f, x) memset(f, x, sizeof(f))\n\n#define bit(x,i) ((x>>(i-1))&1)\n\n#define on(x,i) (x|(1ll<<(i-1)))\n\n#define off(x,i) (x&~(1<<(i-1)))\n\n#define gg exit(0);\n\n\n\n\n\nconst int M=1000000007;\n\n\n\nint n,ret=1,tmp=1;\n\nint f[1000010];\n\n\n\nmain(){\n\n #define task \"TASK\"\n\n //freopen(task\".inp\",\"r\",stdin);\n\n //freopen(task\".out\",\"w\",stdout);\n\n\n\n n=in;\n\n forinc(i,1,n){\n\n f[i]=(f[i]+f[i-1])%M;\n\n tmp=(tmp+f[i])%M;\n\n f[i+3]=(f[i+3]+tmp)%M;\n\n ret=(ret+tmp%M*(n-1)%M*(i==n ? 1 : n)%M)%M;\n\n }\n\n cout<... block followed by exactly one fenced cpp code block.\nDo not mention or rely on hidden tests. The program must read stdin and write stdout.\n\nVisible tests:\nInput:\n2\n\nExpected output:\n4\n\n\nProgram:\n```cpp\n#include \n\nusing namespace std;\n\n\n\nint main(){\n\n constexpr long MOD = 1000000007;\n\n long N;\n\n cin >> N;\n\n long dp{N};\n\n vector sum(4, (N - 1) * N % MOD);\n\n sum[0] = 0;\n\n for(long i = 3, j = 2; i != N + 3; ++i, ++j)sum[i & 3] = (sum[j & 3] - 1 + (dp += sum[(j ^ 2) & 3])) % MOD;\n\n cout << dp % MOD << endl;\n\n return 0;\n\n}\n```", "split": "test", "task_id": "pie_cpp_test_001531"} {"label": "pie_cpp_test_001533", "metadata": {"data_source": "pie-cpp-perf", "gem5_cycles": 17, "hidden_test_count": 1, "problem_id": "p03766", "reference_metric": "runtime_cpu_ns", "reference_value": 17, "source_task_path": "/workspace/runs/pie-tasks-full-20260706/test/pie_cpp_test_001533.json", "split": "test", "subset": "eval", "task_id": "pie_cpp_test_001533", "task_path": "tasks/test/pie_cpp_test_001533.json", "visible_test_count": 1}, "problem_id": "p03766", "prompt": "Optimize the following C++20 program while preserving its exact behavior.\nReturn exactly one ... block followed by exactly one fenced cpp code block.\nDo not mention or rely on hidden tests. The program must read stdin and write stdout.\n\nVisible tests:\nInput:\n2\n\nExpected output:\n4\n\n\nProgram:\n```cpp\n#include\n\n#define re register\n\n#define N 1000005\n\n#define mod 1000000007\n\nusing namespace std;\n\ntemplate\n\ninline void read(re _int&x){\n\n\tre _int res=0,flag=1;re char opt;\n\n\twhile((opt=getchar())<'0'||opt>'9')if(opt=='-')flag=-1;\n\n\twhile(opt>='0'&&opt<='9'){res=(res<<1)+(res<<3)+opt-48;opt=getchar();}\n\n\tx=res*flag;\n\n}\n\ntypedef long long ll; \n\nll n,dp[N],sum[N],ans;\n\nint main(void){\n\n\tre ll i;*dp=1;*sum=1;\n\n\tread(n);ans=(n>2);\n\n\tif(n==1)return puts(\"1\"),0;\n\n\tfor(i=1;i<=n;++i){\n\n\t\t(dp[i]+=(sum[i-1]-((i>=2)?dp[i-2]:0)+mod)%mod)%=mod;\n\n//\t\tprintf(\"%lld %lld\\n\",sum[i-1],((i>=2)?dp[i-2]:0));\n\n\t\tsum[i]=(sum[i-1]+dp[i])%mod;\n\n\t\tif(i... block followed by exactly one fenced cpp code block.\nDo not mention or rely on hidden tests. The program must read stdin and write stdout.\n\nVisible tests:\nInput:\n2\n\nExpected output:\n4\n\n\nProgram:\n```cpp\n#include\n\nusing namespace std;\n\n#ifndef ONLINE_JUDGE\n\n#define dbg(x...) do{cout << \"\\033[32;1m\" << #x << \"->\" ; err(x);} while(0)\n\nvoid err(){cout << \"\\033[39;0m\" << endl;}\n\ntemplate class T,typename t,typename... A>\n\nvoid err(T a,A... x){for (auto v:a) cout << v << ' '; err(x...);}\n\ntemplate\n\nvoid err(T a,A... x){cout << a << ' '; err(x...);}\n\n#else\n\n#define dbg(...)\n\n#endif\n\ntypedef long long ll;\n\ntypedef pair pi;\n\ntypedef vector vi;\n\ntemplate using vc=vector;\n\ntemplate using vvc=vc>;\n\ntemplate void mkuni(vector&v)\n\n{\n\n sort(v.begin(),v.end());\n\n v.erase(unique(v.begin(),v.end()),v.end());\n\n}\n\ntemplate\n\nvoid print(T x,int suc=1)\n\n{\n\n cout<\n\nvoid print(const vector&v,int suc=1)\n\n{\n\n for(int i=0;i>n;\n\n dp[1]=n;\n\n pre[1]=n;\n\n for(int i=2;i<=n;i++)\n\n {\n\n dp[i]=(dp[i-1]+1LL*(n-1)*(n-1)%mod)%mod;\n\n if(i>=3) dp[i]=(dp[i]+pre[i-3])%mod;\n\n if(i==2) dp[i]=(dp[i]+n-1)%mod;\n\n else dp[i]=(dp[i]+n-i+2);\n\n pre[i]=(pre[i-1]+dp[i])%mod;\n\n //dbg(i,dp[i]);\n\n }\n\n cout<