| {"label": "pie_cpp_test_001506", "metadata": {"data_source": "pie-cpp-perf", "gem5_cycles": 11, "hidden_test_count": 1, "problem_id": "p03766", "reference_metric": "runtime_cpu_ns", "reference_value": 11, "source_task_path": "/workspace/runs/pie-tasks-full-20260706/test/pie_cpp_test_001506.json", "split": "test", "subset": "eval", "task_id": "pie_cpp_test_001506", "task_path": "tasks/test/pie_cpp_test_001506.json", "visible_test_count": 1}, "problem_id": "p03766", "prompt": "Optimize the following C++20 program while preserving its exact behavior.\nReturn exactly one <reasoning>...</reasoning> block followed by exactly one fenced cpp code block.\nDo not mention or rely on hidden tests. The program must read stdin and write stdout.\n\nVisible tests:\nInput:\n2\n\nExpected output:\n4\n\n\nProgram:\n```cpp\n#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define int long long\n\n#define in ({int x=0;int c=getchar(),n=0;for(;!isdigit(c);c=getchar()) n=(c=='-');for(;isdigit(c);c=getchar()) x=x*10+c-'0';n?-x:x;})\n\nmt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\n\nint rnd(int l,int r){return l+rng()%(r-l+1);}\n\n#define fasty ios_base::sync_with_stdio(0),cin.tie(0);\n\n#define forinc(a,b,c) for(int a=b,_c=c;a<=_c;++a)\n\n#define fordec(a,b,c) for(int a=b,_c=c;a>=_c;--a)\n\n#define forv(a,b) for(auto&a:b)\n\n#define fi first\n\n#define se second\n\n#define pb push_back\n\n#define ii pair<int,int>\n\n#define mt make_tuple\n\n#define all(a) a.begin(),a.end()\n\n#define reset(f, x) memset(f, x, sizeof(f))\n\n#define bit(x,i) ((x>>(i-1))&1)\n\n#define on(x,i) (x|(1ll<<(i-1)))\n\n#define off(x,i) (x&~(1<<(i-1)))\n\n#define gg exit(0);\n\n\n\n\n\nconst int M=1000000007;\n\n\n\nint n,ret=1,tmp=1;\n\nint f[1000010];\n\n\n\nmain(){\n\n #define task \"TASK\"\n\n //freopen(task\".inp\",\"r\",stdin);\n\n //freopen(task\".out\",\"w\",stdout);\n\n\n\n n=in;\n\n forinc(i,1,n){\n\n f[i]=(f[i]+f[i-1])%M;\n\n tmp=(tmp+f[i])%M;\n\n f[i+3]=(f[i+3]+tmp)%M;\n\n ret=(ret+tmp%M*(n-1)%M*(i==n ? 1 : n)%M)%M;\n\n }\n\n cout<<ret;\n\n}\n```", "split": "test", "task_id": "pie_cpp_test_001506"} |
| {"label": "pie_cpp_test_001531", "metadata": {"data_source": "pie-cpp-perf", "gem5_cycles": 6, "hidden_test_count": 1, "problem_id": "p03766", "reference_metric": "runtime_cpu_ns", "reference_value": 6, "source_task_path": "/workspace/runs/pie-tasks-full-20260706/test/pie_cpp_test_001531.json", "split": "test", "subset": "eval", "task_id": "pie_cpp_test_001531", "task_path": "tasks/test/pie_cpp_test_001531.json", "visible_test_count": 1}, "problem_id": "p03766", "prompt": "Optimize the following C++20 program while preserving its exact behavior.\nReturn exactly one <reasoning>...</reasoning> block followed by exactly one fenced cpp code block.\nDo not mention or rely on hidden tests. The program must read stdin and write stdout.\n\nVisible tests:\nInput:\n2\n\nExpected output:\n4\n\n\nProgram:\n```cpp\n#include <bits/stdc++.h>\n\nusing namespace std;\n\n\n\nint main(){\n\n constexpr long MOD = 1000000007;\n\n long N;\n\n cin >> N;\n\n long dp{N};\n\n vector<long> sum(4, (N - 1) * N % MOD);\n\n sum[0] = 0;\n\n for(long i = 3, j = 2; i != N + 3; ++i, ++j)sum[i & 3] = (sum[j & 3] - 1 + (dp += sum[(j ^ 2) & 3])) % MOD;\n\n cout << dp % MOD << endl;\n\n return 0;\n\n}\n```", "split": "test", "task_id": "pie_cpp_test_001531"} |
| {"label": "pie_cpp_test_001533", "metadata": {"data_source": "pie-cpp-perf", "gem5_cycles": 17, "hidden_test_count": 1, "problem_id": "p03766", "reference_metric": "runtime_cpu_ns", "reference_value": 17, "source_task_path": "/workspace/runs/pie-tasks-full-20260706/test/pie_cpp_test_001533.json", "split": "test", "subset": "eval", "task_id": "pie_cpp_test_001533", "task_path": "tasks/test/pie_cpp_test_001533.json", "visible_test_count": 1}, "problem_id": "p03766", "prompt": "Optimize the following C++20 program while preserving its exact behavior.\nReturn exactly one <reasoning>...</reasoning> block followed by exactly one fenced cpp code block.\nDo not mention or rely on hidden tests. The program must read stdin and write stdout.\n\nVisible tests:\nInput:\n2\n\nExpected output:\n4\n\n\nProgram:\n```cpp\n#include<bits/stdc++.h>\n\n#define re register\n\n#define N 1000005\n\n#define mod 1000000007\n\nusing namespace std;\n\ntemplate<typename _int>\n\ninline void read(re _int&x){\n\n\tre _int res=0,flag=1;re char opt;\n\n\twhile((opt=getchar())<'0'||opt>'9')if(opt=='-')flag=-1;\n\n\twhile(opt>='0'&&opt<='9'){res=(res<<1)+(res<<3)+opt-48;opt=getchar();}\n\n\tx=res*flag;\n\n}\n\ntypedef long long ll; \n\nll n,dp[N],sum[N],ans;\n\nint main(void){\n\n\tre ll i;*dp=1;*sum=1;\n\n\tread(n);ans=(n>2);\n\n\tif(n==1)return puts(\"1\"),0;\n\n\tfor(i=1;i<=n;++i){\n\n\t\t(dp[i]+=(sum[i-1]-((i>=2)?dp[i-2]:0)+mod)%mod)%=mod;\n\n//\t\tprintf(\"%lld %lld\\n\",sum[i-1],((i>=2)?dp[i-2]:0));\n\n\t\tsum[i]=(sum[i-1]+dp[i])%mod;\n\n\t\tif(i<n-1)(ans+=(1ll*(n-1)*(n-1)%mod+min(i+2,n-1))*dp[i]%mod)%=mod;\n\n\t}\n\n\tprintf(\"%lld\\n\",((ans+1ll*n*dp[n-1]%mod)%mod+1ll*(n-1)*(n-1)%mod+1)%mod);\n\n\treturn 0;\n\n}\n```", "split": "test", "task_id": "pie_cpp_test_001533"} |
| {"label": "pie_cpp_test_001549", "metadata": {"data_source": "pie-cpp-perf", "gem5_cycles": 11, "hidden_test_count": 1, "problem_id": "p03766", "reference_metric": "runtime_cpu_ns", "reference_value": 11, "source_task_path": "/workspace/runs/pie-tasks-full-20260706/test/pie_cpp_test_001549.json", "split": "test", "subset": "eval", "task_id": "pie_cpp_test_001549", "task_path": "tasks/test/pie_cpp_test_001549.json", "visible_test_count": 1}, "problem_id": "p03766", "prompt": "Optimize the following C++20 program while preserving its exact behavior.\nReturn exactly one <reasoning>...</reasoning> block followed by exactly one fenced cpp code block.\nDo not mention or rely on hidden tests. The program must read stdin and write stdout.\n\nVisible tests:\nInput:\n2\n\nExpected output:\n4\n\n\nProgram:\n```cpp\n#include<bits/stdc++.h>\n\nusing namespace std;\n\n#ifndef ONLINE_JUDGE\n\n#define dbg(x...) do{cout << \"\\033[32;1m\" << #x << \"->\" ; err(x);} while(0)\n\nvoid err(){cout << \"\\033[39;0m\" << endl;}\n\ntemplate<template<typename...> class T,typename t,typename... A>\n\nvoid err(T<t> a,A... x){for (auto v:a) cout << v << ' '; err(x...);}\n\ntemplate<typename T,typename... A>\n\nvoid err(T a,A... x){cout << a << ' '; err(x...);}\n\n#else\n\n#define dbg(...)\n\n#endif\n\ntypedef long long ll;\n\ntypedef pair<int,int> pi;\n\ntypedef vector<int> vi;\n\ntemplate<class T> using vc=vector<T>;\n\ntemplate<class T> using vvc=vc<vc<T>>;\n\ntemplate<class T> void mkuni(vector<T>&v)\n\n{\n\n sort(v.begin(),v.end());\n\n v.erase(unique(v.begin(),v.end()),v.end());\n\n}\n\ntemplate<class T>\n\nvoid print(T x,int suc=1)\n\n{\n\n cout<<x;\n\n if(suc==1) cout<<'\\n';\n\n else cout<<' ';\n\n}\n\ntemplate<class T>\n\nvoid print(const vector<T>&v,int suc=1)\n\n{\n\n for(int i=0;i<v.size();i++)\n\n print(v[i],i==(int)(v.size())-1?suc:2);\n\n}\n\nconst int INF=0x3f3f3f3f;\n\nconst int mod=1e9+7;\n\nconst int maxn=1e6+7;\n\nll dp[maxn];\n\nll pre[maxn];\n\nint main()\n\n{\n\n\tint n;\n\n cin>>n;\n\n dp[1]=n;\n\n pre[1]=n;\n\n for(int i=2;i<=n;i++)\n\n {\n\n dp[i]=(dp[i-1]+1LL*(n-1)*(n-1)%mod)%mod;\n\n if(i>=3) dp[i]=(dp[i]+pre[i-3])%mod;\n\n if(i==2) dp[i]=(dp[i]+n-1)%mod;\n\n else dp[i]=(dp[i]+n-i+2);\n\n pre[i]=(pre[i-1]+dp[i])%mod;\n\n //dbg(i,dp[i]);\n\n }\n\n cout<<dp[n]<<'\\n';\n\n}\n```", "split": "test", "task_id": "pie_cpp_test_001549"} |
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